California Death Index

Alfred A Seagrave died on May 10, 1958 in Orange County, California. Born in Iowa on September 6, 1861, he lived to be 96 years, 8 months, 4 days old.

His father's last name was Seagrave.

Name Alfred A Seagrave
Sex male
Birth Date September 6, 1861
Death Date May 10, 1958
Age at Death 96 years, 8 months, 4 days old
Birth Place Iowa
Death Place Orange County, California
Father's Last Name Seagrave
Contact