California Death Index

Charles Hyatt Gibson died on August 11, 1949 in Los Angeles County, California. Born in Indiana on December 12, 1868, he lived to be 80 years, 7 months, 30 days old.

His father's last name was Gibson, and mother's maiden name was Hyatt. His Social Security Number was 571-40-0968.

Name Charles Hyatt Gibson
Sex male
Birth Date December 12, 1868
Death Date August 11, 1949
Age at Death 80 years, 7 months, 30 days old
Birth Place Indiana
Death Place Los Angeles County, California
Father's Last Name Gibson
Mother's Maiden Name Hyatt
Social Security Number 571-40-0968
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